s = D ρ = 1017 x 50,000 m-2 = 5x1021atoms m-2
This isn't very much. A single meter of air has about 1027 atoms, so over the entire journey we'll only run through the equivalent of about 5 microns of atmosphere....
It also seems likely to be a bad assumption that the interstellar medium is uniform on any particular scale. We know of lots of small bubbles with a bit more neutral gas and higher densities, but we should probably be visualizing this as a chaotic environment with lots of fluctuations on all scales.
That lack of intervening matter good news and bad news. Friction won't be much of a problem: if our cross section of the main ship is a few hundred meters we're not goring to run into more than a gram or so of matter on the way. If we are hoping to use interstellar material for fuel or reaction mass we need to look over a large area. E.g., how large an area do we need to collect over to get a mass comparable to our ship. One gram of hydrogen is about 6 x 1023 atoms and our ship masses 1000 tons or a billion grams. So the area we need to collect over is
A = 6x1032 / 5x1021 = 1011 m2 = 105km2
If we collect in an area of a circle then
π r2 = 105km2
So we need to collect all of the material within a radius of about 200 km of the center of the ship. Here the fact that most of the matter is ionized could be a big help. In principle at least, we can use magnetic fields to interact with the medium and move it around.
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